5x^2+10x-13000=0

Solution for 5x^2+10x-13000=0 equation:

5x^2+10x-13000=0

a = 5; b = 10; c = -13000;
Δ = b2-4ac
Δ = 102-4·5·(-13000)
Δ = 260100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{260100}=510$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-510}{2*5}=\frac{-520}{10}
=-52
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+510}{2*5}=\frac{500}{10}
=50
$